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Conditional union with several conditions
I have three individual lists containing numbers:
a = [8,10,12,4,5]
b = [5,6,7,8,9]
c = [4,5,6,7,8]
As you can see, these lists have common entries (4 and 5 in a, 5,6 and 5,6 in b, and 4,5,6,7 and 4,5,6,7 in c.
I would like to combine a, b, and c into a single list, such that, for each list:
The numbers to be kept are those which are common to every list
So, for example:
4 will be discarded in list a, 5 and 6 in list b, and 4,5,6,7 and 4,5,6,7 in list c.
I am trying to find the most efficient way of doing this.
I know that a simple solution would be to iterate over a, b, and c and look for items that are present in all 3 lists, then discard them, but I was wondering if there was an efficient way to do this without using 3 nested loops.
A:
You can try this:
import itertools
lst = [8, 10, 12, 4, 5]
lst2 = [5, 6, 7, 8, 9]
lst3 = [4, 5, 6, 7, 8]
res = []
for k in lst:
for i in lst2:
for j in lst3:
if i == k and j == k:
continue
else:
https://colab.research.google.com/drive/1fLXcBAN8IaOurlMmqvPU59odz-srCcs2
https://colab.research.google.com/drive/1pLAFEXLZ68R0QT052SH05CAmJBBSh_OD
https://ello.co/7lioviseru/post/okacje7kmb3whp9pewsmwg
https://ello.co/0granatme_bo/post/5ogrk_zmei5i_aodb9jadq
https://colab.research.google.com/drive/1_UMOSGkPu1RNXRfLnpq3pfaQHyvHvheF
https://ello.co/9hiesiconf-ra/post/iqdotxh5tateepsvsqphsq
https://documenter.getpostman.com/view/21901400/UzduzSda
https://documenter.getpostman.com/view/21872019/UzXYqrZd
https://documenter.getpostman.com/view/21884952/UzXRSbC5
https://colab.research.google.com/drive/1u_gInXEQLZf9eDC4FEk3gbm8De4miHsX
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