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Internet Download Manager (IDM) 6.23 Build 12 Registered (32bit + 64bit Patch) [www.crackingpatching.unblocked2.cc] ·Q:
Base class constructor call from derived classes
I have a base class that calls a constructor function from each of its subclasses. The base class constructor calls these functions:
TrieDict d(dictType);
for(DictItem* p : dict)
{
if(hasSubDict(p))
p->TrieDict(d);
}
dictType is an enum value that defines what type of dictionary the TrieDict object should operate on. In reality, I can define several other enum values, and the above TrieDict constructor is called with no arguments based on the enum value.
The problem is that there are several types of dictionaries that TrieDict can operate on. The constructor does not take a dictionary type as an argument because the argument should be inferred from the enum type, but it never gets called.
Is there a way I can modify this so that the constructor gets called?
The code above is in a header file I have included to several different source files, so I can’t really modify the base class.
A:
You can’t do that from the base class. You would need to either make the argument default to an int or, if you want to maintain binary compatibility with older versions of the code, allow the subclasses to provide the appropriate constructor.
A:
Let the subclasses define a factory method to create a TrieDict for a given dictionary type. That way the factory methods will be invoked and TrieDict will be initialized.
And then there’s a constructor that takes no arguments for the derived classes:
TrieDict::TrieDict(int type)
: dictType(type)
{
// calls other constructors
}
class SomeDict : public TrieDict
{
public:
SomeDict() : TrieDict(/* whatever */)
{
// construct some dictionary
}
};
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