Yds Excellence Grade 10 Grammar Cevap Anahtar
Yds Excellence Grade 10 Grammar Cevap Anahtar
Yds excel nce Grade. Cevap Anahtar 18m Grade 10. Extra features that make it a go-to place when you’re looking for free Kindle books.Q:
Removing leading 0’s from string in C
I know this is probably a simple question, but I can’t get it to work. I have a string that contains leading zeros, and I need to remove those. I have tried the below, and it works fine, just not as I expected. I’m trying to remove each of the leading 0’s in the string.
int main(){
char *str = “000004”;
printf(“%s
“,str);
printf(“%d
“,str[0]);
str[0] = 0;
printf(“%s
“,str);
printf(“%d
“,str[0]);
return 0;
}
The output I get is:
000004
4
000004
4
Can anyone help me out here?
A:
Don’t use the pointer, it’s confusing:
int main() {
char str[] = “000004”;
printf(“%d
“, str[0]);
str[0] = 0;
printf(“%d
“, str[0]);
return 0;
}
A:
Are you sure you are not calling your program with./a.out 0 instead of./a.out “000004”
The confusion comes from the fact that you can use a pointer to a string:
char* s = “0”;
then you can apply the operation you described on the pointer, but with that pointer, it will point to a string literal that will decay to a sequence of characters 0 and that’s why it does what you want.
But if you call your program with./a.out “000004” or./a.out “0”, the memory pointed to by s will contain the “000004” string. So now, you can apply the operation you want without any problem, but the thing is that when you want to access a particular element in that string you have to change it again:
https://colab.research.google.com/drive/1DhAHTLXr5R6ljCXgEoiUs3uaXnc0cEGF
https://colab.research.google.com/drive/1nXREmhJX_T-_jSLq5jXQBHfQBq4j3xBa
https://colab.research.google.com/drive/18V9SgJXp0ct144owCgR8z7LT-HZob5X6
https://colab.research.google.com/drive/1CX115cBN1j42FCGsfg9Lzy9zZoYkb4Q0
https://colab.research.google.com/drive/11pIqp_F9yUAF8V7DbEnxu8PCBZxhpdFc
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